Rust语言计算斐波那契数列
斐波那契数列指的是这样一个数列 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368……..这个数列从第3项开始,每一项都等于前两项之和。f(x) = f(x-1) + f(x-2) 实现计算的Rust代码如下1234567891011121...
斐波那契数列指的是这样一个数列 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368……..这个数列从第3项开始,每一项都等于前两项之和。f(x) = f(x-1) + f(x-2) 实现计算的Rust代码如下1234567891011121...
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